일반화학 7판 솔루션 (Chemistry 7th edition Steven S. Zumdahl (줌달))
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작성일 19-05-10 18:58
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Download : [솔루션] 일반화학 7판 (Chemistry 7th edition Steven S. Zumdahl(줌달))[2].pdf
해답이아니라 풀이집입니다^^
Chapter 1
1. Various geometric formulas are given in Appendix E. (a) Expressing the radius of the Earth as
R = ( 6.37 × 106 m )(10?3 km m ) = 6.37 × 103 km, its circumference is s = 2π R = 2π (6.37 × 103 km) = 4.00 × 104 km. (b) The surface area of Earth is A = 4π R 2 = 4π ( 6.37 × 103 km ) = 5.10 × 108 km 2 .
2
(c) The volume of Earth is V =
4 π 3 4π R = 6.37 × 103 km 3 3
(
)
3
= 1.08 × 1012 km3 .
2. The conversion factors are: 1 gry = 1/10 line , 1 line = 1/12 inch and 1 point = 1/72 inch. The factors imply that 1 gry = (1/10)(1/12)(72 points) = 0.60 point. Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 . 3. Th…(To be continued )
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일반화학 7판 솔루션 (Chemistry 7th edition Steven S. Zumdahl (줌달))
Download : [솔루션] 일반화학 7판 (Chemistry 7th edition Steven S. Zumdahl(줌달))[2].pdf( 12 )
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